2x^2-17x=58

Solution for 2x^2-17x=58 equation:

2x^2-17x=58

We move all terms to the left:

2x^2-17x-(58)=0

a = 2; b = -17; c = -58;
Δ = b2-4ac
Δ = -172-4·2·(-58)
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{753}}{2*2}=\frac{17-\sqrt{753}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{753}}{2*2}=\frac{17+\sqrt{753}}{4}
$